Question

It is known that in Canada, the blood types have the following distribution: 46% O, 42% A, 9% B, 3% AB. A randomly chosen Canadian receives a blood transfusion. Knowing that O is a universal donor, A can only donate to A andAB, B can only donate to B and AB, and AB can only donate to AB, what is the probability that the transfusion is not successful? Graph this distribution.

Answer 1

GIVEN THAT :-

According to the question we have that .

46% =O,

42% =A,

9% =B,

3% =AB

TO FIND :- What is the probability that the transfusion is not successful ?

P(unsuccessful) = P(A) [P(B) + P(AB)] + P(B) [P(A) + P(AB)] + P(O) [P(A) + P(B) + P(AB)]

substituting the values from the above and solving we get that the value as

= 0.3393 [ANSWER]

There for , the probability that the transfusion is not successful =0.3393

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