Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.005; confidence level: 96%; p and q unknown
Solution :
Given that,
=
0.5
1 -
= 1 - 0.5 = 0.5
margin of error = E =0.005
At 96% confidence level the z is ,
= 1 - 96% = 1 - 0.96 = 0.04
/ 2 = 0.04 / 2 = 0.02
Z/2
=2.054 ( Using z table )
Sample size = n = (Z/2
/ E)2 *
* (1 -
)
= (2.054/ 0.005)2 * 0.5 * 0.5
= 42189.16
Sample size = 42189
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