If n=18, ¯ x (x-bar)=48, and s=6, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place
Solution :
Given that,
t /2,df = 2.567
Margin of error = E = t/2,df * (s /n)
= 2.567 * (6 / 18)
Margin of error = E = 3.6
The 98% confidence interval estimate of the population mean is,
- E < < + E
48 - 3.6 < < 48 + 3.6
44.4 < < 51.6
(44.4 , 51.6)
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