Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=990 and x=558 who said "yes." Use a 99 % confidence level.
a) Find the best point estimate of the population proportion
0.564 (Round to three decimal places as needed.)
b) Identify the value of the margin of error E.
E = (Round to three decimal places as needed.)
Solution :
Given that,
n = 990
x = 558
(A)
Point estimate = sample proportion = = x / n = 558 / 990=0.564
1 - = 1- 0.564 =0.436
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576 ( Using z table )
(B)
Margin of error = E = Z/2 * (((( * (1 - )) / n)
= 2.576* (((0.564*0.436) / 990)
= 0.0405986
Margin of error = E = 0.041 rounded
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