Which of the following confidence intervals has the largest critical value? 95% z-inteval or 95% t-interval with 18 degrees of freedom? Why?
solution:
z critical value
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
and
t critical value
n = Degrees of freedom = df = n - 1 =18 - 1 = 17
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2= 0.05 / 2 = 0.025
t /2,df = t0.025,17 = 2.1098 ( using student t table)
t critical value larger than z
when random sample less than 30 we use t critical value thats why critical value comes high compare to z
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