Using the mean and the standard deviation you found in the second question (rounded to four decimals), answer the following probability questions using Stat>Calculators>Normal.
For each, copy and paste the StatCrunch output in the SHOW YOUR WORK.
Here is a short video that shows how to insert multiple graphs into the SHOW WORK area:
SHOW WORK
1. What is the probability that a randomly selected 5-year-old female will be taller than 40 inches tall? (Round to 4 decimal places) nothing
2. What is the probability that a randomly selected 5-year-old female will be shorter than 35 inches tall? (Round to 4 decimal places) nothing
3. What is the probability that a randomly selected 5-year-old female will be between 39 and 47 inches tall? (Round to 4 decimal places) nothing
Question 2
Here is the data again: 44.5 42.4 42.2 46.2 45.7 44.8 43.3 39.5 45.4 43.0 43.4 44.7 38.6 41.6 50.2 46.9 39.6 44.7 36.5 42.7 40.6 47.5 48.4 37.5 45.5 43.3 41.2 40.5 44.4 42.6 42.0 40.3 42.0 42.2 38.5 43.6 40.6 45.0 40.7 36.3 44.5 37.6 42.2 40.3 48.5 41.6 41.7 38.9 39.5 43.6 41.3 38.8 41.9 40.3 42.1 41.9 42.3 44.6 40.5 37.4 44.5 40.7 38.2 42.6 44.0 35.9 43.7 48.1 38.7 46.0 43.4 44.6 37.7 34.6 42.4 42.7 47.0 42.8 39.9 42.3
What is the mean 42.2238
What is the standard deviation? (Round to 4 decimal places) s = 3.1310
Solution:-
1) The probability that a randomly selected 5-year-old female will be taller than 40 inches tall is 0.2388.
x = 40
By applying normal distribution:-
z = 0.7103
P(z > 0.7103) = 0.2388
2) The probability that a randomly selected 5-year-old female will be shorter than 35 inches tall is 0.0104.
x = 35
By applying normal distribution:-
z = - 2.31
P(z < - 2.31) = 0.0104
3) The probability that a randomly selected 5-year-old female will be between 39 and 47 inches tall is 0.7855.
x1 = 39
x2 = 47
By applying normal distribution:-
z1 = - 1.03
z2 = 1.53
P( -1.03 < z < 1.53) = P(z > - 1.03) - P(z > 1.53)
P( -1.03 < z < 1.53) = 0.8485 - 0.0630
P( -1.03 < z < 1.53) = 0.7855
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