In a consumer survey on smartphones, 200 people try Phone I, 150 people try Phone B, and 250 people try Phone S. After the trial period, 165 people are satisfied with Phone I, 130 are satisfied with Phone B, and 225 people are satisfied with Phone S. If a person who tried one of these phone brands is chosen at random and is satisfied, what brand did that person mostly likely try?
Here' the answer. Please write back in case you've not understood any part of it.
Lets first calculate how many consumers are satisfied with their phones
= consumers satisfied with phone I+consumers satisfied with phone B+consumers satisfied with phone S
= 165+130+225
= 520
P(given he' satisfied, he tried phone I) = total number consumers of satisfied with I / total satisfied
= 165/520
= .3173
P(given' he' satisfied, he tried phone B) = total number of consumers satisfied with B/total satisfied
= 130/520
= 0.2500
P(given' he' satisfied, he tried phone S) = total number of consumers satisfied with S/total satisfied
= 225/520
= 0.4327
So, Out of the people who were satisfied , the brand the person' most likely to try is Phone S, as it has the highest probability amongst the 3 phones I, B and S
Answer: Phone S
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