An airline recently polled all of its loyalty card customers and discovered that 22.5% are planning on taking a vacation this year. A flight scheduler for the airline takes a simple random sample of 144 customers. With a 30% chance, the scheduler's sample proportion will be no greater than what value of p̂ ?
z - score =
standard deviation =
sample proportion=
Solution :
z score = ( - ) / = (0.30 - 0.225) / 0.0348 = 2.16
= p * (1-p) / n = 0.225 * 0.775 / 144 = 0.0348
sample proportion = 0.30
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