Exam grades across all sections of introductory statistics at a large university are approximately normally distributed with a mean of 72 and a standard deviation of 11. Use the normal distribution to answer the following questions.
(a) What percent of students scored above a 92 ?
(b) What percent of students scored below a 63 ?
(c) If the lowest 8% of students will be required to attend peer
tutoring sessions, what grade is the cutoff for being required to
attend these sessions?
d) If the highest 9% of students will be given a grade of A, what is the cutoff to get an A?
Let x be the exam grades across all sections of introductory statistics at a large university.
x follows normal distribution with with mean ( µ ) = 72 and standard deviation (σ) = 11
a) P( x > 92) =
= P( z > 1.82 )
=1 - P( z ≤ 1.82 )
= 1 - 0.9656
= 0.034
b) P( x < 63 ) =
= P( z ≤ -0.83 )
= 0.2061
c) P( X ≤ x ) = 0.08
z score corresponding to 0.08 is -1.41
x = z*σ + µ
x = ( -1.41*11 ) + 72
x = 56.49
d) P( X > x ) = 0.09
P( X ≤ x ) = 1 - 0.09 = 0.91
z score corresponding to 0.91 is 1.34
A = z*σ + µ
A = ( 1.34*11 ) + 72
A = 86.74
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