Question

According to a previous year's report, 18% of children have myopia (the condition of nearsightedness). A...

According to a previous year's report, 18% of children have myopia (the condition of nearsightedness). A random sample of 195 children recently had their vision checked.

a) Based on the sample of 195 children, show that the Success/Failure condition is satisfied so that the sampling distribution of p̂ is approximately normal. Don't round the results.

b) Based on the sample of 195 children, find the mean and standard deviation of the sampling distribution of p̂. Round the standard deviation to 4 decimal places.

c) From the sample of 195 children, what is the probability that the proportion of them having myopia is above 22%? Hint: Find P(p̂ > 0.22). Round your z-scores to 2 decimal places but DO NOT ROUND the final answer.

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