Given the population mean, μ = 45, and the population standard deviation, σ = 15 with a sample size of, n = 100.n = 100. Determine P ( x ¯ ≤ 42 ). To do this problem first determine the sampling mean and the sampling standard deviation in order to convert to a z-score. Round your answer to 4 decimals.
Solution :
Given that,
mean = = 45
standard deviation = =15
n = 100
= 45
= / n = 15 / 100=1.5
P( < 42) = P[( - ) / < (42-45) /1.5 ]
= P(z < -2)
Using z table
probability= 0.9772
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