Question

A random sample of 50 perceived age estimates for a model in a cigarette advertisement showed...

A random sample of 50 perceived age estimates for a model in a cigarette advertisement showed that = 26.59 years and that s = 3.7308 years. (a) Use this sample to calculate a 95 percent confidence interval for the population mean age estimate for all viewers of the ad. Assume normality. (Round your answers to 3 decimal places.) The 95 percent confidence interval is [ , ]. (b) Remembering that the cigarette industry requires that models must appear at least 25 years old, does the confidence interval make us 95 percent confident that the population mean perceived age estimate is at least 25? Is the mean perceived age estimate much more than 25? (Click to select) , (Click to select) than 25.

Homework Answers

Answer #1

please like if it helps me please please please

Thank you so much

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of 36 staff members at a local hospital showed an average age of...
A random sample of 36 staff members at a local hospital showed an average age of 25 years. Ages of the staff at the hospital are normally distributed with a population standard deviation of 1.8 years. The 98% confidence interval for the average age of all hospital staff is a) 24.385 to 25.615 b) 23.200 to 26.800 c) 24.301 to 25.699 d) 23.236 to 26.764
A random sample of 14 ​men's resting pulse rates showed a mean of 71.5 beats per...
A random sample of 14 ​men's resting pulse rates showed a mean of 71.5 beats per minute and standard deviation of 19.9. Assume that pulse rates are Normally distributed. Use the table to complete parts​ (a) through​ (c) below. LOADING... Click the icon to view the​ t-table. a. Find a​ 95% confidence interval for the population mean pulse rate of​ men, and report it in a sentence. Choose the correct answer below​ and, if​ necessary, fill in the answer boxes...
A random sample of 20 students at a university showed an average age of 20.9 years...
A random sample of 20 students at a university showed an average age of 20.9 years and a sample standard deviation of 2.5 years. The 98% confidence interval for the true average age of all students in the university is? Enter in the upper limit of your confidence interval.
A random sample of 20 students at a university showed an average age of 21.5 years...
A random sample of 20 students at a university showed an average age of 21.5 years and a sample standard deviation of 2.8 years. The 98% confidence interval for the true average age of all students in the university is? Enter in the upper limit of your confidence interval. ( round to 4 decimal places)
A random sample of 100 credit sales in a department store showed a sample mean of...
A random sample of 100 credit sales in a department store showed a sample mean of $64. The population standard deviation is known to be $16. A) Provide a 99% confidence interval for the population mean. B) Provide a 95% confidence interval for the population mean. C) Describe the effect of a lower confidence level on the margin of error.
A random sample of Ohio cemeteries shows that the average age at death of Revolutionary War...
A random sample of Ohio cemeteries shows that the average age at death of Revolutionary War veterans is 67 years (n = 25, s = 7). Another such random sample showed that the average age at death for Civil War veterans who survived the war is 48 years (n = 78, s = 10). Find the 95% confidence interval estimating the population difference between the age at death of these two groups of veterans assuming not equal variances
1.A survey of households in a small town showed that in 850 of 1,200 sampled households,...
1.A survey of households in a small town showed that in 850 of 1,200 sampled households, at least one member attended a town meeting during the year. Using the 99% level of confidence, what is the confidence interval for the proportion of households represented at a town meeting? 2.A survey of an urban university (population of 25,450) showed that 750 of 1,100 students sampled attended a home football game during the season. Using the 99% level of confidence, what is...
In a random sample of 100 viewers, 72% had a favourable impression of a new TV...
In a random sample of 100 viewers, 72% had a favourable impression of a new TV ad campaign. (a)Test the hypothesis that fewer than 80% of the population of all viewers have a favourable view of the ad campaign. Use the .05 level of significance. Explain your conclusion. (b)Construct a 95% confidence interval for the proportion of the population of all viewers who have a favourable view of the ad campaign. Interpret your results Please show all work! I am...
An advertising agency for a cereal company wants to know the age of people watching "Fists...
An advertising agency for a cereal company wants to know the age of people watching "Fists of Fury Television" on Saturday mornings. A random sample of 50 viewers showed an average age of 12.7 years. From previous experience it is known that r= 2.9 years. Find a 90% confidence interval for the mean age all viewers. How large should our sample be in the previous question, if we want to be sure that the sample mean is written 0.5 years...
4. A pediatrician’s records showed the mean height of a random sample of 25 girls aged...
4. A pediatrician’s records showed the mean height of a random sample of 25 girls aged 12 months to be 29.53 inches with a standard deviation of 1.0953 inches. a. Construct a 95% confidence interval for the true mean height. b. What sample size would be needed for 95 percent confidence and an error of +/- .20 inches?