Question

The amount of corn chips dispensed into a 19?-ounce bag by the dispensing machine has been identified at possessing a normal distribution with a mean of 19.5 ounces and a standard deviation of 0.2 ounce. Suppose 100 bags of chips were randomly selected from this dispensing machine. Find the probability that the sample mean weight of these 100 bags exceeded 19.6 ounces.

Answer 1

Solution :

= / n = 0.2 / 100 = 0.02

P( 19.6) = 1 - P( 19.6)

= 1 - P[( - ) / (19.6 - 19.5) / 0.02]

= 1 - P(z 5)

= 1 - 1

= 0