Question

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proportions of boys and girls under 10 years old who are afraid of spiders. Assume the "worst case" scenario for the value of both sample proportions. We want a 9999% confidence level and for the error to be smaller than 0.04.0.04.

Answer:

(b) Again find the sample size required, as in part (a), but with the knowledge that a similar student last year found that the proportion of boys afraid of spiders is 0.53 and the proportion of girls afraid of spiders was 0.61.

Answer: please show yu work o=and what function, if any you used on the calculator. thank you!

Answer 1

a)

p1          =	0.5
q1=1-p1=	0.5
p2          =	0.5
q2=1-p2=	0.5
here margin of error E =	0.04
for99% CI crtiical Z          =	2.576	from excel:normsinv((1+0.99)/2)
sample size n (p1q1+p2q2)*(Z/E)2=	2074

b)

p1          =	0.53
q1=1-p1=	0.47
p2          =	0.61
q2=1-p2=	0.39
here margin of error E =	0.04
for99% CI crtiical Z          =	2.576
sample size n (p1q1+p2q2)*(Z/E)2=	2020