Let Y = ex where X is normally distributed with μ = 3.7 and σ = 0.5. Compute the following values.
a. Compute P(Y ≤ 9.8). (Round your intermediate calculations to at least 4 decimal places, “z” value to 2 decimal places, and final answer to 4 decimal places.)
b. Compute P(6.0 < Y <
6.9). (Leave no cells blank - be certain to enter "0"
wherever required. Round your intermediate calculations to at least
4 decimal places, “z” value to 2 decimal places, and final
answer to 4 decimal places.)
This is a normal distribution question with a) x = 9.8
P(x < 9.8)=?
The z-score at x = 9.8 is,
z = 12.2
This implies that
b) x1 = 6.0
x2 = 6.9
P(6.0 < x < 6.9)=? This implies that
PS: you have to refer z score table to find the final probabilities.
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