Question

Question: Suppose that the number of errors in one page of local newspaper follows the Poisson distribution with an average of 4.

A) What is the probability that the sports section consisting of 4 pages will have at least 13 errors?

B) What is the probability that the local news section consisting of 5 pages will have no more than 17 errors?

C) What is the probability that that there will be between 10 and 18 errors in the main section of the newspaper consisting of 1 pages?

Answer 1

a)

expected number of errors in 4 pages =4*4=16=

hence probability that the sports section consisting of 4 pages will have at least 13 errors

=P(X>=13) =1-P(X<=12)=1- =1-0.1931=0.8069

b)

expected number of errors in 5 pages =4*5=20=​

hence probability that the sports section consisting of 5 pages will have no more than 17 errors

=P(X<=17) = =0.2970

c)expected number of errors in 1 page =4=​

probability that that there will be between 10 and 18 errors in the main section of the newspaper consisting of 1 pages=P(10<=X<=18) = =0.0081