The manufacturer of a certain candy states that 15% of the
candies are brown, 15% yellow, 25% red, 20% blue, 10% orange, 15%
green. A student randomly selected a giant bag of candy and counted
the number of each color. The results are in the table below. Does
the candy follow the stated distribution?
(a) Complete the table. Report all answers accurate to 2 decimal
places.
Color | Brown | Yellow | Red | Blue | Orange | Green |
Frequency | 21 | 23 | 24 | 26 | 7 | 16 |
Expected Frequency |
(b) Select the null and alternative hypotheses.
(c) What is the chi-square test-statistic for this data? Round your
answer to 3 decimals.
χ2=χ2=
(d) What is the P-Value? Round your answer to 4 decimals.
P-Value =
(e) For significance level alpha 0.01, what would be the decision
of this hypothesis test?
(f) Select the conclusion.
The statistical software output for this problem is :
H0H0: PBr=0.15, PY =0.15, PR =0.25, PB =0.20,PO =0.1,PG =
0.15,
Ha at least one proportion is different .
χ2 = 7.461
P-value = 0.1885
Fail to reject the Null Hypothesis
There is not sufficient evidence to support that the claim that at least one proportion is different. Therefore, the candy follows the stated distribution
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