Null hypothesis (H_{0}): The true difference in mean hemoglobin change for pregnant women not exposed to herbicides versus those who are somewhat exposed is 0 g/dL. (µ_{bottle} – µ_{both} = 0 g/dL)
Research hypothesis (H_{1}): The true difference in mean hemoglobin change for pregnant women not exposed to herbicides versus those who are somewhat exposed is not 0 g/dL. (µ_{bottle} – µ_{both} ≠ 0 g/dL)
SAS Output:
The TTEST Procedure
Variable: change
group 
Method 
Mean 
95% CL Mean 
Std Dev 
95% CL Std Dev 

2 
2.0326 
1.9846 
2.0806 
0.4329 
0.4015 
0.4696 

3 
3.3348 
3.2932 
3.3763 
0.4192 
0.3918 
0.4507 

Diff (12) 
Satterthwaite 
1.3022 
1.3655 
1.2388 
Method 
Variances 
DF 
t Value 
Pr > t 
Satterthwaite 
Unequal 
663.42 
40.36 
<.0001 
a. What is the 95% confidence interval for the difference in group means? Please write in interval notation: (smaller, larger)
b. What is the interpretation of the 95% confidence interval for the difference in group means?
c. Would you reject or fail to reject the null hypothesis? (Use α=0.05.) Why?
d. What is the conclusion of the hypothesis test? (Write in terms of the research hypothesis.)
a)
95% CI (1.3655 ,1.2388)
...............
B)
WE ARE 95% CONFIDENT THAT TRUE MEAN DIFFERENCE BETWEEN LIE IN THIS INTERVAL
............
C)
P VALUE < 0.05 , REJECT Ho
.......
d)
conclusion : there is enough evidence to conclude that The true difference in mean hemoglobin change for pregnant women not exposed to herbicides versus those who are somewhat exposed is not 0 g/dL.
.................
Please let me know in case of any doubt.
Thanks in advance!
Please upvote!
Get Answers For Free
Most questions answered within 1 hours.