Question

# Null hypothesis (H0): The true difference in mean hemoglobin change for pregnant women not exposed to...

Null hypothesis (H0): The true difference in mean hemoglobin change for pregnant women not exposed to herbicides versus those who are somewhat exposed is 0 g/dL. (µbottle – µboth = 0 g/dL)

Research hypothesis (H1): The true difference in mean hemoglobin change for pregnant women not exposed to herbicides versus those who are somewhat exposed is not 0 g/dL. (µbottle – µboth ≠ 0 g/dL)

SAS Output:

The TTEST Procedure

Variable: change

 group Method Mean 95% CL Mean Std Dev 95% CL Std Dev 2 2.0326 1.9846 2.0806 0.4329 0.4015 0.4696 3 3.3348 3.2932 3.3763 0.4192 0.3918 0.4507 Diff (1-2) Satterthwaite -1.3022 -1.3655 -1.2388
 Method Variances DF t Value Pr > |t| Satterthwaite Unequal 663.42 -40.36 <.0001

a. What is the 95% confidence interval for the difference in group means? Please write in interval notation: (smaller, larger)

b. What is the interpretation of the 95% confidence interval for the difference in group means?

c. Would you reject or fail to reject the null hypothesis? (Use α=0.05.) Why?

d. What is the conclusion of the hypothesis test? (Write in terms of the research hypothesis.)

a)

95% CI (-1.3655 ,-1.2388)

...............

B)

WE ARE 95% CONFIDENT THAT TRUE MEAN DIFFERENCE BETWEEN LIE IN THIS INTERVAL

............

C)

P VALUE < 0.05 , REJECT Ho

.......

d)

conclusion : there is enough evidence to conclude that  The true difference in mean hemoglobin change for pregnant women not exposed to herbicides versus those who are somewhat exposed is not 0 g/dL.

.................

Please let me know in case of any doubt.

#### Earn Coins

Coins can be redeemed for fabulous gifts.