The following table shows age distribution and location of a random sample of 166 buffalo in a national park.
Age | Lamar District | Nez Perce District | Firehole District | Row Total |
Calf | 10 | 13 | 18 | 41 |
Yearling | 10 | 14 | 9 | 33 |
Adult | 38 | 29 | 25 | 92 |
Column Total | 58 | 56 | 52 | 166 |
Use a chi-square test to determine if age distribution and location are independent at the 0.05 level of significance.
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: Age distribution and location are not
independent.
H1: Age distribution and location are not
independent.H0: Age distribution and location
are independent.
H1: Age distribution and location are not
independent. H0: Age
distribution and location are not independent.
H1: Age distribution and location are
independent.H0: Age distribution and location
are independent.
H1: Age distribution and location are
independent.
(b) Find the value of the chi-square statistic for the sample.
(Round the expected frequencies to at least three decimal places.
Round the test statistic to three decimal places.)
Are all the expected frequencies greater than 5?
YesNo
What sampling distribution will you use?
normalchi-square Student's tbinomialuniform
What are the degrees of freedom?
(c) Find or estimate the P-value of the sample test
statistic. (Round your answer to three decimal places.)
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis of independence?
Since the P-value > α, we fail to reject the null hypothesis.Since the P-value > α, we reject the null hypothesis. Since the P-value ≤ α, we reject the null hypothesis.Since the P-value ≤ α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the
application.
At the 5% level of significance, there is sufficient evidence to conclude that age distribution and location are not independent.At the 5% level of significance, there is insufficient evidence to conclude that age distribution and location are not independent.
Answer:
a)
Level of significance =0.05
Null and Alternate hypothesis:
H0: Age distribution and location are independent.
H1: Age distribution and location are not independent.
b)
Chi square test statistic X2 =6.247
Expected frequencies greater than 5: Yes
Sampling distribution: Chi square
Degrees of freedom= 4
c) p-value = 0.181
p value > alpha
d)
Since the p value >alpha, we fail to reject the null
hypothesis
e)
There is insufficient evidence to conclude that age distribution
and location are not independent.
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