For this problem, carry at least four digits after the decimal
in your calculations. Answers may vary slightly due to
rounding.
In a random sample of 60 professional actors, it was found that 36
were extroverts.
(a) Let p represent the proportion of all actors who are extroverts. Find a point estimate for p. (Round your answer to four decimal places.)
(b) Find a 95% confidence interval for p. (Round your
answers to two decimal places.)
lower limit | |
upper limit |
Solution :
Given that,
a) Point estimate = sample proportion = = x / n = 36 / 60 = 0.6000
1 - = 1 - 0.6000 = 0.4000
Z/2 = Z0.025 = 1.96
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.96 * (((0.6000 * 0.4000) / 60)
= 0.1240
b) A 95% confidence interval for population proportion p is ,
- E < p < + E
0.6000 - 0.1240 < p < 0.6000 + 0.1240
0.48 < p < 0.72
lower limit = 0.48
upper limit = 0.72
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