Question

# Please show your work 11.3.2 Levi-Strauss Co manufactures clothing. The quality control department measures weekly values...

11.3.2

Levi-Strauss Co manufactures clothing. The quality control department measures weekly values of different suppliers for the percentage difference of waste between the layout on the computer and the actual waste when the clothing is made (called run-up). The data is in table #11.3.3, and there are some negative values because sometimes the supplier is able to layout the pattern better than the computer ("Waste run up," 2013). Do the data show that there is a difference between some of the suppliers? Test at the 1% level.

Table #11.3.3: Run-ups for Different Plants Making Levi Strauss Clothing

 Plant 1 Plant 2 Plant 3 Plant 4 Plant 5 1.2 16.4 12.1 11.5 24 10.1 -6 9.7 10.2 -3.7 -2 -11.6 7.4 3.8 8.2 1.5 -1.3 -2.1 8.3 9.2 -3 4 10.1 6.6 -9.3 -0.7 17 4.7 10.2 8 3.2 3.8 4.6 8.8 15.8 2.7 4.3 3.9 2.7 22.3 -3.2 10.4 3.6 5.1 3.1 -1.7 4.2 9.6 11.2 16.8 2.4 8.5 9.8 5.9 11.3 0.3 6.3 6.5 13 12.3 3.5 9 5.7 6.8 16.9 -0.8 7.1 5.1 14.5 19.4 4.3 3.4 5.2 2.8 19.7 -0.8 7.3 13 3 -3.9 7.1 42.7 7.6 0.9 3.4 1.4 70.2 1.5 0.7 3 8.5 2.4 6 1.3 2.9

The hypothesis being tested is:

H0: µ1 = µ2 = µ3 = µ4 = µ5

Ha: At least one means is not equal

 Mean n Std. Dev 4.52 22 10.032 Plant 1 8.83 22 15.353 Plant 2 4.83 19 4.403 Plant 3 7.49 19 3.657 Plant 4 10.38 13 9.555 Plant 5 6.98 95 9.893 Total ANOVA table Source SS df MS F p-value Treatment 450.921 4 112.7302 1.16 .3340 Error 8,749.088 90 97.2121 Total 9,200.009 94

The p-value is 0.3340.

Since the p-value (0.3340) is greater than the significance level (0.01), we fail to reject the null hypothesis.

Therefore, we cannot conclude that there is a difference between some of the suppliers.

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