Describe the sampling distribution of p. N = 24,000, n= 450, p = 0.7
Solution
Given that,
p = 0.7
1 - p = 1 - 0.7 = 0.3
n = 450
approximately normal np 0.05N and np(1 - p) 10
= p = 0.7
[p ( 1 - p ) / n] = [(0.7 * 0.3) / 450 ] = 0.0216
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