Question

The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 29 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 29 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on his friend's course) is -3.16 strokes and the standard deviation of the differences is 8.017 strokes. The owner uses this information to calculate the 95% confidence paired t-interval of (-6.21, -0.11). Which statement is the correct interpretation of this interval?

Question 11 options: 1) We are certain the average difference in scores between the two courses for all golfers is between -6.21 and -0.11. 2) The proportion of all golfers that had a difference in scores between the two courses is 95%. 3) We are 95% confident that the average difference in scores between the two courses for all golfers is between -6.21 and -0.11. 4) We are 95% confident that the difference between the average score on the owner's golf course and the average score on the friend's golf course is between -6.21 and -0.11. 5) We are 95% confident that the average difference in the scores of the golfers sampled is between -6.21 and -0.11.

Answer 1

3) We are 95% confident that the average difference in scores between the two courses for all golfers is between -6.21 and -0.11.

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Paired t-interval : Average difference :

Difference : Score on the his course - the score on the his friend course;

Then Average of this difference

Two-sample t-interval : difference between two means.

(Average score on his course - Average score on his friend course.

For the given problem, Paired t-interval is being calculated. Hence that answer.

answered by: anonymous