Question

The recommended dietary allowances of iron for women under the age of 51 is 18 milligrams...

The recommended dietary allowances of iron for women under the age of 51 is 18 milligrams (mg) per day. A medical researcher studying women living in a certain region suspected that the women were getting less than the daily allowance of iron, on average. The researcher took a random sample of women under the age of 51 from the region and measured their daily iron intakes. The following hypotheses were tested at the significance level of α = 0.05 for the population mean µ of the daily iron intake for women in the region.
H0: µ = 18
HA: µ < 18
All conditions for inference are met, and the resulting p-value was 0.031.
Which of the following is an appropriate conclusion?

(A)   The p-value is less than α, and the null hypothesis should be rejected. There is convincing statistical evidence that the mean daily intake of iron for women in the region is less than the recommended 18 mg.

(B)   The p-value is less than α, and the null hypothesis should be rejected. There is not convincing statistical evidence that the mean daily intake of iron for women in the region is less than the recommended 18 mg.

(C)   The p-value is less than α, and the null hypothesis should not be rejected. There is not convincing statistical evidence that the mean daily intake of iron for women in the region is less than the recommended 18 mg.

D-The p-value is greater than α, and the null hypothesis should be rejected. There is convincing statistical evidence that the mean daily intake of iron for women in the region is less than the recommended 18 mg.

E-The p-value is greater than α, and the null hypothesis should not be rejected. There is not convincing statistical evidence that the mean daily intake of iron for women in the region is less than the recommended 18 mg.

Homework Answers

Answer #1

Conclusion on p-value:

Given,

hypotheses were tested at the significance level of α = 0.05 And p-value = 0.031

So, P-value (0.031) is less than 0.05 then reject H0.

The alternative hypothesis is HA: µ < 18

i.e.population mean µ of the daily iron intake for women in the region is less than the recommended 18 mg.

So, Answer A is correct.

(A)   The p-value is less than α, and the null hypothesis should be rejected. There is convincing statistical evidence that the mean daily intake of iron for women in the region is less than the recommended 18 mg.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The recommended daily allowance of iron for females aged 19–50 is 18 mg/day. A careful measurement...
The recommended daily allowance of iron for females aged 19–50 is 18 mg/day. A careful measurement of the daily iron intake of 15 women yielded a mean daily intake of 16.2 mg with sample standard deviation 4.7 mg. a. Assuming that daily iron intake in women is normally distributed, perform the test that the actual mean daily intake for all women is different from 18 mg/day, at the 10% level of significance. b. The sample mean is less than 18,...
The recommended daily dietary allowance for zinc among males older than age 50 years is 15...
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 114, x = 11.3, and s = 6.65. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use α = 0.05.) State the appropriate null and alternative hypotheses. H0: μ =...
The recommended dietary allowance (RDA) of vitamin C for women is 75 milligrams (mg) per day....
The recommended dietary allowance (RDA) of vitamin C for women is 75 milligrams (mg) per day. A hypothesis test, with a significance level of 0.05, is to be performed to decide whether adult women are, on average, getting less than the RDA of 75 mg per day. A researcher gathers data from a random sample of women in order to carry out the test. Based on this data, she calculates a test statistic of t = -2.207 and a P-Value...
A dietary assessment was performed on 51 boys 9 to 11 years of age whose families...
A dietary assessment was performed on 51 boys 9 to 11 years of age whose families were below poverty level. The mean daily iron intake among these boys was found to be 12.50 mg with standard deviation 4.75 mg. Suppose the mean daily iron intake among a large population of 9 to 11 year old boys from all income strata is 14.44 mg. a. Conduct a 5 step significance test with alpha = .01 of whether the mean iron intake...
The recommended daily dietary allowance for zinc among males older than age 50 years is 15...
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 115, x = 12.1, and s = 6.57. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use α = 0.05.) H0: μ = 15 Ha: μ < 15 Calculate the...
The recommended dietary allowance​ (RDA) of iron for adult females is 18milligrams​ (mg) per day. The...
The recommended dietary allowance​ (RDA) of iron for adult females is 18milligrams​ (mg) per day. The given iron intakes​ (mg) were obtained for 45 random adult females. At the 1​% significance​ level, do the data suggest that adult females​ are, on​ average, getting less than the RDA of 18mg of​ iron? Assume that the population standard deviation is 4.9mg. Preliminary data analyses indicate that applying the​ z-test is reasonable.​ note (sample mean = 14.66mg) state the hypothesis for one-mean z...
The recommended daily dietary allowance for zinc among men older than 50 (years) is 15 mg/day....
The recommended daily dietary allowance for zinc among men older than 50 (years) is 15 mg/day. In a random sample of 115 men ages 65-74, the sample mean was 11.3 mg/day and sample standard deviation was 6.43 mg/day. Does this suggest that average daily zinc intake of all men ages 65-74 is below the recommended allowance? Do a 4-part hypothesis test ((Hypotheses, assumptions, calculation and conclusion)with α = .01. Show your work. For p-value use R code.
A nutritionist claims that children under the age of 10 years are consuming more than the...
A nutritionist claims that children under the age of 10 years are consuming more than the U.S. Food and Drug Administration’s recommended daily allowance of sodium, which is 2300 mg. To test this claim, she obtains a random sample of 16 children under the age of 10, and measures their daily consumption of sodium. The mean amount of sodium consumed is 2500 mg with a standard deviation of 320 mg. Is there significant evidence to support the claim of the...
1. In testing a null hypothesis H0 versus an alternative Ha, H0 is ALWAYS rejected if...
1. In testing a null hypothesis H0 versus an alternative Ha, H0 is ALWAYS rejected if A. at least one sample observation falls in the non-rejection region. B. the test statistic value is less than the critical value. C. p-value ≥ α where α is the level of significance. 1 D. p-value < α where α is the level of significance. 2. In testing a null hypothesis H0 : µ = 0 vs H0 : µ > 0, suppose Z...
A nutritionist claims that children under the age of 10 years are consuming more than the...
A nutritionist claims that children under the age of 10 years are consuming more than the U.S. Food and Drug Administration’s recommended daily allowance of sodium, which is 2400mg. To test the claim, she obtained a random sample of 75 children under the age of 10 and measured their daily consumption of sodium. The sample mean amount of sodium consumed was 2993 mg and the sample standard deviation was 1889 mg. Is there significant evidence to support the nutritionist’s claim...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT