Create a 99% confidence interval for the mean using following data. Explain/show what you did to arrive are your answer.
x |
10 |
20 |
90 |
50 |
20 |
30 |
40 |
10 |
80 |
10 |
Mean = X / n = 360 / 10 = 36
Sample standard devaition S = sqrt [ (X2 - n 2 ) / n - 1 ]
= sqrt [ (20600 - 10 * 362 ) / 9 ]
= 29.1357
99% Confidence Interval
X̅ ± t(α/2, n-1) S/√(n)
t(α/2, n-1) = t(0.01 /2, 10- 1 ) = 3.25
36 ± 3.25 * 29.1357/√(10)
Lower Limit = 36 - 3.5 * 29.1357/√(10)
Lower Limit = 6.06
Upper Limit = 36 + 3.25 * 29.1357/√(10)
Upper Limit = 65.94
99% Confidence interval is ( 6.06 , 65.94
)
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