Scores on an English test are normally distributed with a mean of 37.6 and a standard deviation of 7.6. Find the score that separates the top 59% from the bottom 41% Group of answer choices 35.9 39.3 42.1 33.1
Given that,
mean = = 37.6
standard deviation = =7.6
Using standard normal table,
P(Z > z) = 39%
= 1 - P(Z < z) = 0.39
= P(Z < z ) = 1 - 0.39
= P(Z < z ) = 0.61.
z =0.28 (using standard normal (Z) table )
Using z-score formula
x = z * +
x= 0.28 *7.6+37.6
x= 39.3
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