Scores on a test have a mean of 66 and Q3 is 80. The scores have a distribution that is approximately normal. Find the standard deviation. Round your answer to the nearest tenth. Group of answer choices 10.5 20.9 18.7 9.4
Solution:-
Given that,
mean = = 66
x = 80
The z dist'n Third quartile is,
P(Z < z) = 75%
= P(Z < z) = 0.75
= P(Z < 0.67 ) = 0.75
z = 0.67
Using z-score formula,
x = z * +
80 = 0.67 * + 66
= 80 - 66 / 0.67
= 20.9
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