You have a pot with 100 balls. 20 of them are red, 50 are blue and 30 are green. You decide to draw 5 balls from the pot without replacement (i.e. you don't put a ball back in the pot once it has been taken out). What is the probability of drawing five blue balls?
Give your answer to 3 decimal places.
A) Given data
Total balls=100
Red balls=20
Blue balls=50
Green balls=30
Sample space is =Drawing 5 balls from the pot without replacement
=100C5
=100!/((100-5)!×(5!)
=100×99×98×97×96×95!/(95!×5!)
=100×99×98×97×96/(5!)
=(9034502400)/120
=75287520
Event is=drawing of 5 blue balls out of 50 blue balls
=50C5
=50!/((50-5)!×(5!)
=50×49×48×47×46×45!/(45!×5!)
=50×49×48×47×46/(5!)
=(254251200)/(120)
=2118760
Now , required probability=Event/sample space
=2118760/(75287520)
=0.0281
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