It is known that the population variance equals 529. With a .95 probability, the sample size that needs to be taken if the desired margin of error is 4 or less is
508.
128.
127.
509.
Solution :
Given that,
Population variance = 529
So, standard deviation = = 23
margin of error = E = 4
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Sample size = n = ((Z/2 * ) / E)2
= ((1.96 * 23) /4 )2
= 127
Sample size = 127
Option 3rd is
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