null hypothesis:Ho μ | = | 3 | ||
Alternate Hypothesis:Ha μ | < | 3 | ||
for 0.05 level with left tail test , critical z= | -1.645 | (from excel:normsinv(0.05) | ||
Decision rule:reject Ho if test statistic z<-1.645 |
population mean μ= | 3 | |
sample mean 'x̄= | 2.750 | |
sample size n= | 50 | |
std deviation σ= | 1.000 | |
std error ='σx=σ/√n=1/√50= | 0.1414 | |
z statistic= ='(x̄-μ)/σx=(2.75-3)/0.141= | -1.77 |
since test statistic falls in rejection region we reject null hypothesis |
we have sufficient evidence to conclude that the mean waiting time is less than 3 minutes |
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