Question

**1. Make a claim.**

30% of coffee drinkers drunk more than 1 cup of coffee per day

**2. Check the conditions and see if the requirements are
met.**

H0: p =0.30

Ha: p >0.30

Significance level = .05

Critical value = 1.960

N=30

X=14

Right tailed p-value

Np>5 and nq>5

Use: Z test for population proportion

**3. Write out the calculator command that you were using
and the result.**

**Stat->test->1-propZ test:**

Po: .30

X=14

N=30

>Po

Calculate

**Results:**

Z= 1.992047

P=.023218

p̂=.466

n=30

**4 Write a conclusion without using complicated
wordings.**

**is this correct?**

Answer #1

**Please don't hesitate to give a "thumbs up" in case
you're satisfied with the answer**

1. Claim is correct

2. Claim should come always as the alternative hypothesis, which is
correct in this case

3. Righly defined right t-test.

3. The calculator command is correct.

4. p-value = .0232

5. The p-value is less than .05 ( significance level assumed in the
question), which means that

the null hypothesis is rejected and we "Accept" the alternative
hypothesis . i.e. Claim is TRUE

i.,e. YES, 30% of coffee drinkers drunk more than 1 cup of coffee per day

Is this correct? My claims is that 30% of coffee
drinkers consume more than 1 cup of coffee per day. I asked 30
people if they consume more than 1 cup of coffee per day and 14
people stated they consume more than 1 cup of coffee per
day.
1. Make a claim.
30% of coffee drinkers drunk more than 1 cup of coffee per
day
2. Check the conditions and see if the requirements are
met.
H0: p =0.30...

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BIOS 376 Homework 7
1. A professor claims that the mean IQ for college students is
92. He collects a random sample of 85 college students to test this
claim and the mean IQ from the sample is 84.
(a) What are the null and alternative hypotheses to test the
initial claim? (1 pt)
(b) Using R, compute the test statistic. Assume the population
standard deviation of IQ scores for college students is 17.6
points. (1 pt)
(c) Using R,...

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