1. Make a claim.
30% of coffee drinkers drunk more than 1 cup of coffee per day
2. Check the conditions and see if the requirements are met.
H0: p =0.30
Ha: p >0.30
Significance level = .05
Critical value = 1.960
N=30
X=14
Right tailed p-value
Np>5 and nq>5
Use: Z test for population proportion
3. Write out the calculator command that you were using and the result.
Stat->test->1-propZ test:
Po: .30
X=14
N=30
>Po
Calculate
Results:
Z= 1.992047
P=.023218
p̂=.466
n=30
4 Write a conclusion without using complicated wordings.
is this correct?
Please don't hesitate to give a "thumbs up" in case you're satisfied with the answer
1. Claim is correct
2. Claim should come always as the alternative hypothesis, which is
correct in this case
3. Righly defined right t-test.
3. The calculator command is correct.
4. p-value = .0232
5. The p-value is less than .05 ( significance level assumed in the
question), which means that
the null hypothesis is rejected and we "Accept" the alternative
hypothesis . i.e. Claim is TRUE
i.,e. YES, 30% of coffee drinkers drunk more than 1 cup of coffee per day
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