Question

A group of 200 patients tested a new medication. Some tried the new medication, and the...

A group of

200

patients tested a new medication.
Some tried the new medication, and the rest took the old medication.

The results are reported in the following two-way frequency table.

No improvement Improvement
Old medication

73

37

New medication

63

27

A patient is chosen at random from this group.

Complete the following. Write your answers as decimals.

(a)Find the probability that the patient showed improvement.

=P(improvement)

(b)Find the probability that the patient showed improvement, given that he took the new medication.

=P(improvement | new medication)

(c)Is there evidence that a patient who takes the new medication is more likely to show improvement than a randomly chosen patient from the group?

Yes, because the probability found in part (b) is much greater than the probability found in part (a).

No, because the probability found in part (b) is much greater than the probability found in part (a).

Yes, because the probability found in part (a) is much greater than the probability found in part (b).

No, because the probability found in part (a) is much greater than the probability found in part (b).

Yes, because the probability found in part (b) is about the same as the probability found in part (a).

No, because the probability found in part (b) is about the same as the probability found in part (a).

Homework Answers

Answer #1

The tabulated data is given as

No improvement Improvement TOTAL
Old medication 73 37 110
New medication 63 27 90
TOTAL 136 64 200

(a) Find the probability that the patient showed improvement.

P(improvement)= 64/200

= 0.32

(b) Find the probability that the patient showed improvement, given that he took the new medication.

=0.3

(c)Is there evidence that a patient who takes the new medication is more likely to show improvement than a randomly chosen patient from the group?

No, because the probability found in part (b) is about the same as the probability found in part (a)

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