Question

A survey found that 50% of cats and 60% of dogs have pet licenses in the city of Saskatoon. These results were based on random samples of 100 cats and 100 dogs. Test at the 5% significance level that proportion of cats that have licenses is less than the proportion of dogs that have licenses. What is the p-value and what is your conclusion?

Answer #1

p1cap = X1/N1 = 50/100 = 0.5

p1cap = X2/N2 = 60/100 = 0.6

pcap = (X1 + X2)/(N1 + N2) = (50+60)/(100+100) = 0.55

Below are the null and alternative Hypothesis,

Null Hypothesis, H0: p1 = p2

Alternate Hypothesis, Ha: p1 < p2

Test statistic

z = (p1cap - p2cap)/sqrt(pcap * (1-pcap) * (1/N1 + 1/N2))

z = (0.5-0.6)/sqrt(0.55*(1-0.55)*(1/100 + 1/100))

z = -1.42

P-value Approach

P-value = 0.0778

Not sufficient evidence to conclude that the cats that have licenses is less than the proportion of dogs that have licenses.

A survey found that 50% of cats and 60% of dogs have pet
licenses in the city of Saskatoon. These results were based on
random samples of 100 cats and 100 dogs. Test at the 5%
significance level that proportion of cats that have licenses is
less than the proportion of dogs that have licenses. What is the
p-value and what is your conclusion?

Statistical Methods Question 14: A researcher collected data from
random samples of 100 cats and 100 dogs. The researcher found that
50 of the cats and 60 of the digs in tbe sample had pet licenses.
Test at the 5% significance level that the proportion of cats that
have licenses is less than the proportion of dogs that have
licenses. What is the p-value for this set, what is your
conclusion?

A pet association claims that the mean annual cost of food for
dogs and cats are the same. The results for samples for the two
types of pets are shown below. Is there enough evidence at ? = 0.05
to reject the pet association’s claim? Assume the population
variances are not equal. Assume the samples are random and
independent and the populations are normally distributed.
Dogs Cats
?̅̅1̅ = $210 ?̅̅2̅ = $187
?1 = 35 ?1 = 31
?1...

A sample of 125 men was taken and it was found that 31 owned
cats.
A sample of 148 women was taken and it was found that 73 owned
cats.
Test the claim that the proportion of men who own cats is equal to
than the proportion of women who own cats at the .10 significance
level.
Claim: Which corresponds to:
Opposite: Which corresponds to:
The test is:
The test statistic is: Z= (Two decimal places)
The P-value is:...

I believe that 67% of US households own a pet. A survey of 50
employees out of 120 employees of PRO Systems showed that 49 owned
a pet. Test this hypothesis at the .15 significance level. Assume a
random sample. Include the null and alternative hypothesis, alpha
value, p-value, and a conclusion. Make sure that you use
appropriate terminology, specify whether you are using the
classical method or the p-value method, and fully explain your
solution.

6. Are pedigreed dogs more likely to exhibit neurotic behavior
compared to mixed breed dogs? A pet psychologist studied a random
sample of 400 dogs consisting of 160 with pedigrees and 240 mixed
breed dogs. 56 of the pedigreed dogs and 60 of the mixed breed dogs
were judged to be neurotic. Test at 5% significance level whether
the proportion of neurotics among pedigreed dogs is significantly
higher than the proportion among mixed breed dogs. Show all work
and formulas

The proportion of people that own cats is 60%. A veterinarian
believes that this proportion is larger than 60% and surveys 400
people. Test the veterinarian's claim at the α=0.10 significance
level.
Preliminary:
Is it safe to assume that n≤0.05 of all subjects in the
population?
Yes
No
Verify np(1−p)≥. Round your answer to one decimal
place.
np(1−p)=
Test the claim:
The null and alternative hypotheses are
H0:μ≥0.6
Ha:μ<0.6
H0:μ=0.6
Ha:μ≠0.6
H0:p=0.6
Ha:p≠0.6
H0:p≤0.6
Ha:p>0.6
H0:μ≤0.6
Ha:μ>0.6
H0:p=0.6
Ha:p<0.6
The...

#1 Are people who live in Texas more likely to own a pet than
people who live in Georgia? A survey of 50 Texans found that 74% of
them own a pet. A survey of 55 Georgians 35 of them are pet owners.
Answer the question by performing a hypothesis test using a 0.05
level of significance. State the Hypotheses and your conclusion
using the z-value and p-value.

Test the claim that the proportion of people who own cats is
significantly different than 20% at the 0.01 significance
level.
The alternative hypothesis would be:
μ>0.2
p≠0.2
μ≠0.2
p>0.2
p<0.2
μ<0.2
The test is:
right-tailed
two-tailed
left-tailed
Based on a sample of 500 people, 16% owned cats
The test statistic is: (to 2 decimals)
The p-value is: (to 2 decimals)
Based on this we:
Reject the null hypothesis
Fail to reject the null hypothesis
The conclusion is:
At the...

A recent survey stated that 37% of pet owners talk to their pets
on the telephone. A veterinarian believes that the proportion
should be lower than the survey's claim. In a random sample of 180
pet owners, 33.9% of them said they spoke to their pets on the
telephone. Find the following while performing a hypothesis test to
see if there is sufficient evidence that the proportion of pet
owners that talk to their pets on the telephone is lower...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 4 minutes ago

asked 10 minutes ago

asked 39 minutes ago

asked 46 minutes ago

asked 49 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago