Question

In the Journal of Marketing Research (November 1996), Gupta studied the extent to which the purchase...

In the Journal of Marketing Research (November 1996), Gupta studied the extent to which the purchase behavior of scanner panels is representative of overall brand preferences. A scanner panel is a sample of households whose purchase data are recorded when a magnetic identification card is presented at a store checkout. The table below gives peanut butter purchase data collected by the A. C. Nielson Company using a panel of 2,500 households in Sioux Falls, South Dakota. The data were collected over 102 weeks. The table also gives the market shares obtained by recording all peanut butter purchases at the same stores during the same period.

Number of Purchases by Household Panel Market
Shares
Jif 18 oz. 3,169 19.15%
Jif 28 1,870 10.71
Jif 40 749 5.16
Peter Pan 10 4,026 16.38
Skippy 18 6,238 27.45
Skippy 28 1,661 12.68
Skippy 40 1,443 8.47
Total 19,156
Goodness-of-Fit Test
obs expected O – E (O – E)2/E % of chisq
3,169 3,668.374 -499.374 67.980 8.11
1,870 2,051.608 -181.608 16.076 1.92
749 988.450 -239.450 58.006 6.92
4,026 3,137.753 888.247 251.448 29.98
6,238 5,258.322 979.678 182.524 21.76
1,661 2,428.981 -767.981 242.816 28.95
1,443 1,622.513 -179.513 19.861 2.37
19,156 19,156.001 -.001 838.711 100.01

(a) Show that it is appropriate to carry out a chi-square test.

Each expected value is ?               

(b) Test to determine whether the purchase behavior of the panel of 2,500 households is consistent with the purchase behavior of the population of all peanut butter purchasers. Assume here that purchase decisions by panel members are reasonably independent, and set ? = .05. (Round your answers ?2to 2 decimal places and ?2.05 to 3 decimal places.)

Homework Answers

Answer #1

(a) Show that it is appropriate to carry out a chi-square test.

Each expected value is ? 5

for continuity the expected value for each cell should be ? 5

(b) Test to determine whether the purchase behavior of the panel of 2,500 households is consistent with the purchase behavior of the population of all peanut butter purchasers. Assume here that purchase decisions by panel members are reasonably independent, and set ? = .05.(Round your answers ?2to 2 decimal places and ?2.05 to 3 decimal places.)

since the calculated  ?2=sum((O-E)2/E)=838.71 with df=n-1=7-1=6

is more than the critical ?2(.05,6)=12.592 , so we reject the null hypothesis that households is consistent with the purchase behavior of the population of all peanut butter purchasers .

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