Blood lead levels were examined in 363 adolescents and the average blood lead level was 2.2 and a standard deviation of 0.5. Calculate the lower bound of a 95% confidence interval for the true mean blood lead level of the adolescents.
Solution :
Given that,
Z = Z0.05 = 1.645
Margin of error = E = Z
* (
/n)
= 1.645 * ( 0.5 / 363
)
= 0.04
At 95% lower confidence interval estimate of the population mean
is,
- E
= 2.2 - 0.04 = 2.16
lower bound = 2.16
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