Question

PLEASE ANSWER WITH INSTRUCTIONS/STEPS FOR TI-84 ~thank you!!!

In a survey of 3001 ?adults, a poll asked people whether they smoked cigarettes and whether they always wear a seat belt in a car. The table shows the results of the survey. For each? activity, define a success as finding an individual that participates in the hazardous activity.   

	No seat belt, success	Seat belt, failure
Smoke, success	63	438
Do not smoke, failure	330	2170

A) Calculate the test statistic (H0: p1=p2 // H1: p1?p2 with ?=0.05 level of significance

B) Calculate the p-value.

I don't actually care about the answers, just the process to get the answers (using a Ti-84). Specifically, what commands to use on a Ti-84 to get the answer. I get how to get a result for matched pairs and indepdendent trials, but I don't understand how to calculate success and failure (this type of question) on a Ti-84.

PLEASE ANSWER WITH INSTRUCTIONS/STEPS FOR TI-84 ~thank you!!!

Answer 1

Sol:

H0:p1=p2

H1:p1 not = p2

alpha=0.05

p1^=x/1n1=63/330=0.1909091

p2^=x2/n2=438/2170=0.2018433

Z=p1^-p2^/sqrt(p1^(1-p1)/n1+p2^(1-p2^)/n2

Z=0.1909091-0.2018433/sqrt(0.1909091*(1-0.1909091)/330+0.2018433*(1-0.2018433)/2170))

Z=-0.469

To get p value in R type:

2*pnorm(-0.469,mean=0,sd=1)

p=0.6390696

how to do in TI84?

Follow below instructions:

p=0.64

Test for difference in proportions

go to STATS>TESTS

select option6:2-propZtest

ENTER X1=63

N1=330

X2=438

N2=2170

Select p1 not equal to p2

press enter