The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 221 customers on the number of hours cars are parked and the amount they are charged. |
Number of Hours | Frequency | Amount Charged | ||||
1 | 19 | $ | 3 | |||
2 | 34 | 6 | ||||
3 | 46 | 12 | ||||
4 | 39 | 18 | ||||
5 | 35 | 21 | ||||
6 | 13 | 24 | ||||
7 | 7 | 26 | ||||
8 | 28 | 30 | ||||
221 | ||||||
a. |
Convert the information on the number of hours parked to a probability distribution. (Round your answers to 3 decimal places.) |
Hours | Probability |
1 | |
2 | |
3 | |
4 | |
5 | |
6 | |
7 | |
8 | |
a-2. | Is this a discrete or a continuous probability distribution? |
|
b-1. |
Find the mean and the standard deviation of the number of hours parked. (Do not round intermediate calculations. Round your final answers to 3 decimal places.) |
Mean | |
Standard deviation | |
b-2. |
How long is a typical customer parked? (Do not round intermediate calculations. Round your final answers to 3 decimal places.) |
The typical customer is parked for | hours |
c. |
Find the mean and the standard deviation of the amount charged. (Do not round intermediate calculations. Round your final answers to 3 decimal places.) |
Mean | |
Standard deviation | |
a) dividing each frequency cell with total frequency:
hours | probability |
1 | 0.086 |
2 | 0.154 |
3 | 0.208 |
4 | 0.176 |
5 | 0.158 |
6 | 0.059 |
7 | 0.032 |
8 | 0.127 |
a-2) discrete
b-1)
mean =4.106 ( please try 4.104 if this comes wrong)
std deviation =2.074 ( please try 2.072 if this comes wrong)
b-2) The typical customer is parked for 4.106 hours
c)
mean =16.222 ( please try 16.218 if this comes wrong)
std deviation =8.351 ( please try 8.344 if this comes wrong)
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