A sample of 31 observations is selected from a normal population. The sample mean is 11, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.05 significance level.
H0: μ ≤ 10
H1: μ > 10
Solution :
= 10
=11
=3
n = 31
This is the right tailed test .
The null and alternative hypothesis is ,
H0 : < 10
Ha : > 10
Test statistic = z
= ( - ) / / n
= (11-10) / 3 / 32
= 1.85
Test statistic = z = 1.85
P(z > 1.85) = 1 - P(z < 1.85 ) = 0.9678
P-value =0.0322
= 0.05
P-value <
0.0322 < 0.05
Reject the null hypothesis .
There is sufficient evidence to suggest that
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