Each of three supermarket chains in the Denver area claims to have the lowest overall prices. As part of an investigative study on supermarket advertising, a local television station conducted a study by randomly selecting nine grocery items. Then, on the same day, an intern was sent to each of the three stores to purchase the nine items. From the receipts, the following data was recorded. At the 0.05 significance level, is there a difference in the mean price for the nine items between the three supermarkets?
Item | Super's | Ralph's | Lowblaws |
1 | $1.12 | $1.02 | $1.07 |
2 | 1.14 | 1.10 | 1.21 |
3 | 1.72 | 1.97 | 2.08 |
4 | 2.22 | 2.09 | 2.32 |
5 | 2.40 | 2.10 | 2.30 |
6 | 4.04 | 4.32 | 4.15 |
7 | 5.05 | 4.95 | 5.05 |
8 | 4.68 | 4.13 | 4.67 |
9 | 5.52 | 5.46 | 5.86 |
For blocks (Items):
H0: μ1 = μ2 = ... μ9
H0: μ1 ≠ μ2 ≠ ... μ9
Alternate hypothesis
H1: There is no difference in the item means.
H1: There is a difference in the item means.
What is the decision rule for both? (Round your answers to 2 decimal places.)
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Complete an ANOVA table. (Round your SS, MS to 3 decimal places, and F to 2 decimal places.)
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What is your decision regarding the null hypothesis? The decision for the F value (Stores) at 0.05 significance is:
Do not reject H0
Reject H0
The decision for the F value (Items) at 0.05 significance is:
Do not reject H0
Reject H0
Is there a difference in the item means and in the store means?
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ANSWER:
Given that,
3)
Option A is correct.
4}
H1 :There is a difference in the item means.
5)
reject Ho if F>
for stores: >3.63
for items >2.59
Source of Variation | SS | df | MS | F |
stores | 0.137 | 2 | 0.069 | 3.10 |
items | 71.614 | 8 | 8.952 | 405.62 |
Error | 0.353 | 16 | 0.022 | |
Total | 72.104 | 26 |
6)
Source of Variation | SS | df | MS | F |
stores | 0.137 | 2 | 0.069 | 3.10 |
items | 71.614 | 8 | 8.952 | 405.62 |
Error | 0.353 | 16 | 0.022 | |
Total | 72.104 | 26 |
7)
do not reject Ho
8)
reject Ho
9)
there is a difference in the item means but not in the store means
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