Question

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.)

A. Compute the probability that exactly four of the six M&M’s are yellow.

B. Compute the probability that four or five of the six M&M’s are yellow.

C. Compute the probability that at most four of the six M&M’s are yellow.

D. Compute the probability that at least four of the six M&M’s are yellow.

Answer 1

(a) Probability = 0.0055

(b) Probability = 0.0004

(c) Probability = 0.9996

(d) Probability = 0.0059

	6	n
	0.15	p
		cumulative
X	P(X)	probability
0	0.3771	0.3771
1	0.3993	0.7765
2	0.1762	0.9527
3	0.0415	0.9941
4	0.0055	0.9996
5	0.0004	1.0000
6	0.0000	1.0000
	1.0000
	0.900	expected value
	0.765	variance
	0.875	standard deviation

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