Question

use
the standard normla table to find the z-score thag corresponds to
tbe given percentile . if the area is not in the table use the
entry closest to the area . if the area is halfway between two
entries use the z-score halfway between the corresponding z-scores

1. the z-score that corresponds to P80 is ??

(round to two decimal places as needed)

find the z -score that has 97.5% of the distribution's area to
its left

1. the z-score is ???

(round to two decimal places as needed)

1. the z-score that corresponds to P7 is ??

(round to two decimal places as needed)

Answer #1

Use the standard normal table to find the z-score that
corresponds to the cumulative area 0.7454. If the area is not in
the table, use the entry closest to the area. If the area is
halfway between two entries, use the z-score halfway between the
corresponding z-scores.
z=_____? (Type an integer or decimal rounded to three decimal
places as needed.)

16. Use a table of cumulative areas under the normal curve to
find the z-score that corresponds to the given cumulative area. If
the area is not in the table, use the entry closest to the area.
If the area is halfway between two entries, use thez-score
halfway between the corresponding z-scores. If convenient, use
technology to find the z-score.
0.049
The cumulative area corresponds to the z-score of __.
17. Use the standard normal table to find the z-score...

Use a table of cumulative areas under the normal curve to find
the z-score that corresponds to the given cumulative area. If the
area is not in the table, use the entry closest to the area. If
the area is halfway between two entries, use the z-score halfway
between the corresponding z-scores. If convenient, use technology
to find the z-score. .051

Please answer the questions below
1. Find the z-score that has 48.8% of the distribution's area
to its left?
2. Find the z-scores for which 5% of the distribution's area
lies between minus−z and z?
3. Find the indicated area under the standard normal curve.
Between z=0 and z=1.34 The area between
z=0 and z=1.34 under the standard normal curve is?

please answer all
1.) Use Table A to find the value z of a standard
Normal variable that satisfies each of the following conditions.
(Use the value of z from Table A that comes closest to
satisfying the condition.) In each case, sketch a standard Normal
curve with your value of z marked on the axis. (Round your
answers to two decimal places.)
(a) The point z with 64% of the observations falling
below it
z =
(b) The point...

For 12 – 15, round to 2DP.
12. Find the z-score for which 70% of the area is to the
right.
_________
13. Find the z-score that corresponds to P6
________________
14. Find the z-scores for which 60% of the
distribution’s area lies between − z and z.
__________

Q1-. A normal distribution has a mean of 15 and a standard
deviation of 2. Find the value that corresponds to the 75th
percentile. Round your answer to two decimal places.
Q2-.Tyrell's SAT math score was in the 64th percentile. If all
SAT math scores are normally distributed with a mean of 500 and a
standard deviation of 100, what is Tyrell's math score? Round your
answer to the nearest whole number.
Q3-.Find the z-score that cuts off an area...

The values of z-score are given.
1a.) Find the area under the normal curve to the right of
z = -0.86. Round the answer to four decimal places.
The area under the normal curve to the right of z =
-0.86 is ____.
1c.) Find the area under the normal curve between z =
-0.32 and z = 0.92. Round the answer to four decimal
places.
The area under the normal curve between z = -0.32 and
z = 0.92...

1. Find the value z of a standard Normal variable
Z that satisfies each of the following conditions. (If you
use Table A, report the value of z that comes closest to
satisfying the condition.) In each case, sketch a standard Normal
curve with your value of z marked on the axis.
38% of the observations fall below z
70% of the observations fall above z
2.) Jorge scores 2090 on the SAT. Assuming that both tests
measure the same...

Find the critical value z Subscript alpha divided by 2 that
corresponds to the given confidence level. 83% z Subscript alpha
divided by 2 equals nothing (Round to two decimal places as
needed.)

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