Question

Question 1 (1 point) The percentage of scores located between the mean and two standard deviations above the mean in the standard normal distribution is ___________. Question 1 options: a) 34.13% b) 47.72% c) -34.13% d) 50% Save Question 2 (1 point) The z-score that cuts off the upper 17% of the distribution is _________. Question 2 options: a) 1.28 b) 1.96 c) 0.95 d) -1.03 Save Question 3 (1 point) With a mean of 100 and a standard deviation of 15, an IQ scores of 85 would correspond to what z-score value? Question 3 options: a) -1 b) -1.5 c) 1 d) 1.5 Save Question 4 (1 point) For a z-score of -1.5, the proportion between the Mean and z is _____________. Question 4 options: a) -.4332 b) .2967 c) .4332 d) -.4984 Save Question 5 (1 point) For a z-score of -0.5, the proportion in the tail is ____________. Question 5 options: a) -.3085 b) .0096 c) .3085 d) -.0064 Please help with my homework I am struggling with. Thank you

Answer 1

Solution:-

1) b) The percentage of scores located between the mean and two standard deviations above the mean in the standard normal distribution is 47.72%.

2) c) The z-score that cuts off the upper 17% of the distribution is 0.95.

p-value for the upper 17% = 1 - 0.17 = 0.83

z-score for the p-value(0.83) = 0.955

3) a) IQ scores of 85 would correspond to z-score = - 1.

4) c) The proportion between the Mean and z is 0.4332.

P(- 1.5 < z < 0) = P(z > - 1.50) + P(z > 0)

P(- 1.5 < z < 0) = 0.9332 - 0.50

P(- 1.5 < z < 0) = 0.4332

5) c) For a z-score of -0.5, the proportion in the tail is 0.3085.