Question

Run a significant test and find the p value

Ho: p=0.43

Ha: p<0.43

p ^ = 0.5

n=10

Answer #1

Solution :

This is the left tailed test .

The null and alternative hypothesis is

H0 : p = 0.43

Ha : p < 0.43

= 0.5

P0 = 0.43

1 - P0 = 1 - 0.43 = 0.57

Test statistic = z =

= - P0 / [P0 * (1 - P0 ) / n]

= 0.5 - 0.43/ [(0.43 * 0.57) / 10]

Test statistic = z = 0.45

P(z > 0.45) = 1 - P(z < 0.45) = 1 - 0.6736

P-value = 0.3264

Find test statistic and P VALUE and make conclusion for
PROPORTION: x=35, n=200, Ho: p=25%, H1: p<25%, confidence
level=0.05
Find test statistic and P VALUE and make conclusion for MEAN:
x̄=37, s=10.2, n=30, Ho: μ=32, H1: μ≠32, confidence level=0.01
Find test statistic AND P VALUE and make conclusion for TWO
PROPORTIONS: x1 = 6, n1 = 315, x2 = 80, n2 = 320, Ho: p1 = p2, HA:
p1 < p2, α = 0.1

In a test of the hypothesis Ho: μ = 50
versus Ha: μ ≠ 50,
with a sample of n = 100 has a Sample Mean = 49.4 and Sample
Standard Deviation, S = 4.1.
(a) Find the p-value for the test. (b)
Interpret the
p-value for the test, using
an α =
0.10.

1.
using a significance level of 0.05, find P value
identify Ho & Ha.
show whether left tailed, right or two tailed.
p> .32 , z = -2.41
same for : t= -0.29 , n = 16
2. There is about 200 single people in the united states in
the 1040s, they are randomly selected. the mesn income of the group
of 200 is about 28,000 and has a standard deviaton of
$40,000.
cl : 95%

1). Conduct the appropriate hypothesis test with the following
information, and provide your p-value as your final
answer. The null hypothesis states that H0:=
250 versus the alternative Ha: > 250. The sample of
size 26 resulted in a mean of 255.0 and a standard deviation of
8.79.
Find the p-value in this example.
2). Conduct the appropriate hypothesis test with the following
information, and provide your p-value as your final
answer. The null hypothesis states that H0: =
0.75 versus the...

The p-value and the value of α for a test of Ho: μ =
150 are provided for each part. Make the appropriate
conclusion regarding Ho.
P-value = .217, α = .10
P-value = .033, α = .05
P-value = .001, α = .05
P-value = .866, α = .01
P-value = .025, α = .01

9.12 Suppose a 95% confidence interval for p1−p2 is (0.43,
0.51). A researcher wants to test H0∶p1−p2=0.5 versus Ha∶p1−p2≠0.5
at α=0.05 significance level. What is the p−value for this
test?

You wish to test the following claim (HA) at a significance
level of a= 0.002
Ho: μ = 77.4
Ha : μ > 77.4
You believe the population is normally distributed, but you do not
know the standard deviation. You obtain a sample of size
n = 14 with mean M = 82.9 and a standard deviation of SD
=8.6
What is the test statistic for this sample? (Report answer
accurate to three decimal places.)
test statistic =
What is the...

In a test of the hypotheses Ho : μ1 = μ2 versus Ha : μ1 6= μ2 ,
the observed sample results in a given p-value. Given that the 95%
confidence interval for μ1 - μ2 is (-.21.5 , -5.0) based on this
give an appropriate p-value for this test.

In order to test HO: p = 0.59 versus H1: p
< 0.59, use n = 150 and x = 78 as your sample
proportion.
Using your TI 83/84 calculator device, find the P-value with the
appropriate Hypothesis Test
Use a critical level α = 0.05 and decide to Accept or Reject
HO with the valid reason for the decision.

With Ha : μ ≠ 151
you obtain a test statistic of z=1.54. Find the p-value accurate to
4 decimal places.
p-value =
Please provide a step-by-step for a TI-84 calculator.

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