Question

Run a significant test and find the p value

Ho: p=0.43

Ha: p<0.43

p ^ = 0.5

n=10

Answer 1

Solution :

This is the left tailed test .

The null and alternative hypothesis is

H0 : p = 0.43

Ha : p < 0.43

= 0.5

P0 = 0.43

1 - P0 = 1 - 0.43 = 0.57

Test statistic = z =

= - P0 / [P0 * (1 - P0 ) / n]

= 0.5 - 0.43/ [(0.43 * 0.57) / 10]

Test statistic = z = 0.45

P(z > 0.45) = 1 - P(z < 0.45) = 1 - 0.6736

P-value = 0.3264