The effectiveness of a new bug repellent is tested on 19 subjects for a 10 hour period. (Assume normally distributed population.) Based on the number and location of the bug bites, the percentage of surface area exposed protected from bites was calculated for each of the subjects. The results were as follows: ?⎯⎯⎯=95, ?=14 The new repellent is considered effective if it provides a percent repellency of at least 89. Using ?=0.05, construct a hypothesis test with null hypothesis ?=89 and alternative hypothesis ?>89 to determine whether the mean repellency of the new bug repellent is greater than 89 by computing the following:
null hypothesis: HO: μ | = | 89 | ||
Alternate Hypothesis: Ha: μ | > | 89 | ||
0.05 level with right tail test and n-1= 18 df, critical t= | 1.734 | |||
Decision rule :reject Ho if test statistic t>1.734 | ||||
population mean μ= | 89 | |||
sample mean 'x̄= | 95.000 | |||
sample size n= | 19.00 | |||
sample std deviation s= | 14.000 | |||
std error 'sx=s/√n= | 3.212 | |||
test stat t ='(x-μ)*√n/sx= | 1.868 | |||
p value = | 0.0391 |
since test statistic falls in rejection region we reject null hypothesis | ||||
we have sufficient evidence to conclude that the mean repellency of the new bug repellent is greater than 89 |
Get Answers For Free
Most questions answered within 1 hours.