Question

A simple random sample from a population with a normal distribution of

107107

body temperatures has

x overbarxequals=98.3098.30degrees Upper F°F

and

sequals=0.680.68degrees Upper F°F.

Construct

aa

9999%

confidence interval estimate of the standard deviation of body temperature of all healthy humans.

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Click the icon to view the table of Chi-Square critical values.

Answer #1

Chi square critical values at 0.01 level with 106 df = L = 72.251 , R = 147.247

99% confidence interval for is

sqrt [ - t * S / R] < < sqrt [ + t * S /L]

sqrt [ 106 * 0.68^{2} / 147.247] <
< sqrt [ 106 * 0.68^{2} / 72.251 ]

0.5770 < < 0.8236

99% CI is **( 0.5770 , 0.8236)**

A simple random sample from a population with a normal
distribution of 99 body temperatures has x
overbarequals98.90degrees Upper F and sequals0.62degrees Upper F.
Construct a 95% confidence interval estimate of the standard
deviation of body temperature of all healthy humans. LOADING...
Click the icon to view the table of Chi-Square critical
values.

A simple random sample from a population with a normal
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( Can you tell me exactly how can find XL2
XR2. )

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____F<o<____ F

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___°F < σ < ___°F
(Round to two decimal places as needed.)
Is it safe to conclude that the population standard deviation is
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