Question

In a random sample of eight cell​ phones, the mean full retail price was ​$450.00 and...

In a random sample of eight cell​ phones, the mean full retail price was ​$450.00 and the standard deviation was ​$208.00. Assume the population is normally distributed and use the​ t-distribution to find the margin of error and construct a 90​% confidence interval for the population mean mu. Interpret the results.

Identify the margin of error.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a random sample of eleven cell​ phones, the mean full retail price was 401.00 and...
In a random sample of eleven cell​ phones, the mean full retail price was 401.00 and the standard deviation was 166.00. Assume the population is normally distributed and use the​ t-distribution to find the margin of error and construct a 90​% confidence interval for the population mean μ. 1-Identify the margin of error. 2-Construct a 90​% confidence interval for the population mean.
In a random sample of six ​people, the mean driving distance to work was 18.3 miles...
In a random sample of six ​people, the mean driving distance to work was 18.3 miles and the standard deviation was 4.3 miles. Assume the population is normally distributed and use the​ t-distribution to find the margin of error and construct a 90​% confidence interval for the population mean mu. Interpret the results. Identify the margin of error.
In a random sample of 18 ​people, the mean commute time to work was 33.1 minutes...
In a random sample of 18 ​people, the mean commute time to work was 33.1 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 98​% confidence interval for the population mean mu . What is the margin of error of mu? Interpret the results. The confidence interval for the population mean mu is: The margin of error of mu is:
In a random sample of five ​people, the mean driving distance to work was 24.9 miles...
In a random sample of five ​people, the mean driving distance to work was 24.9 miles and the standard deviation was 4.3 miles. Assuming the population is normally distributed and using the​ t-distribution, a 99​%confidence interval for the population mean mu is left parenthesis 16.0 comma 33.8 right parenthesis ​(and the margin of error is 8.9​). Through​ research, it has been found that the population standard deviation of driving distances to work is 3.3 Using the standard normal distribution with...
In a random sample of 18 ​people, the mean commute time to work was 32.4 minutes...
In a random sample of 18 ​people, the mean commute time to work was 32.4 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 99​% confidence interval for the population mean mu. What is the margin of error of mu​? Interpret the results.
In a random sample of 20 ​people, the mean commute time to work was 32.6 minutes...
In a random sample of 20 ​people, the mean commute time to work was 32.6 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 80​% confidence interval for the population mean mu. What is the margin of error of u​? Interpret the results. The confidence interval for the population mean u is? What is the margin of error?
In a random sample of 21 ​people, the mean commute time to work was 31.3 minutes...
In a random sample of 21 ​people, the mean commute time to work was 31.3 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 98​% confidence interval for the population mean mu. What is the margin of error of mu​? Interpret the results. The confidence interval for the population mean mu is left parenthesis nothing comma nothing right parenthesis . ​(Round to one decimal place as​ needed.) The...
In a random sample of twelve ​people, the mean driving distance to work was 24.5 miles...
In a random sample of twelve ​people, the mean driving distance to work was 24.5 miles and the standard deviation was 5.2 miles. Assume the population is normally distributed and use the​ t-distribution to find the margin of error and construct a 90% confidence interval for the population mean μ. Identify the margin of error. Construct a 90​% confidence interval for the population mean.
In a random sample of six mobile devices, the mean repair cost was $60.00 and the...
In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results. The 99% confidence interval for the population μ is (_, _)
In a random sample of six mobile​ devices, the mean repair cost was $75.00 and the...
In a random sample of six mobile​ devices, the mean repair cost was $75.00 and the standard deviation was $13.0013.00. Assume the population is normally distributed and use a​ t-distribution to find the margin of error and construct a 95​% confidence interval for the population mean. Interpret the results. The 95​% confidence interval for the population mean μ is