Question

A recent national survey found that high school students watched an average (mean) of 7.1 movies per month with a population standard deviation of 1.0. The distribution of number of movies watched per month follows the normal distribution. A random sample of 33 college students revealed that the mean number of movies watched last month was 6.2. At the 0.05 significance level, can we conclude that college students watch fewer movies a month than high school students?

State the null hypothesis and the alternate hypothesis.

*H*_{0}: μ ≥ 7.1; *H*_{1}: μ <
7.1

*H*_{0}: μ = 7.1; *H*_{1}: μ ≠
7.1

*H*_{0}: μ > 7.1; *H*_{1}: μ =
7.1

*H*_{0}: μ ≤ 7.1; *H*_{1}: μ >
7.1

State the decision rule.

Reject *H*_{1} if *z* < –1.645

Reject *H*_{0} if *z* > –1.645

Reject *H*_{1} if *z* > –1.645

Reject *H*_{0} if *z* < –1.645

Compute the value of the test statistic. **(Negative
amount should be indicated by a minus sign. Round your answer to 2
decimal places.)**

What is your decision regarding *H*_{0}?

Reject *H*_{0}

Do not reject *H*_{0}

What is the *p*-value? **(Round your answer to 4
decimal places.)**

Answer #1

the null hypothesis and the alternate hypothesis.

H0: μ ≥ 7.1; H1: μ < 7.1

Decision rule:

Reject H0 if z < –1.645

We have given,

Population mean for given example =7.1

Sample mean= 6.2

Population standard deviation = 1

Sample size for given example = 33

Level of significance = 0.05

Z test statistic formula

the value of the test statistic=-5.17

Z test statistic value < Z critical value therefore we reject H0.

P value is approximately 0 ..................by using NORMSDIST(-5.17)

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