SCORES: -3, -3, -3, -3, -3, -3, -3, -3, -3,
-2, -2, -2, -2, -2, -2, -2, -2, -2,
2,
-1, -1, -1, -1, -1, -1, -1
0, 0, 0, 0, 0, 0, 0, 0, 0, 0
Sample size ____36________________
Sample mean __-1.39______________
Sample standard deviation ____1.29_____________
Estimated standard error _____.22________________
Based on the table shown in SPSS, state the following values associated with the test statistic:
Mean difference ___-1.39___________________
t obtained (t) ______-6.44___________________
Degrees of freedom (df) _______35___________________
Significance (2-tailed) _______.00____________________
Based on the value of the test statistic, what is the decision for a one-sample t test? (Circle one)
Retain the null hypothesis Reject the null hypothesis
Compute Cohen's d and state the size of the effect as small, medium, or large. (Show your work.) In a sentence, also state the number of standard deviations that scores have shifted in the population. Note: The tables in SPSS give you all the data you need to compute effect size.
Compute proportion of variance using eta-squared or omega-squared, and state the size of the effect as small, medium, or large. (Show your work.) In a sentence, also state the proportion of variance in the dependent variable that can be explained by the factor. The tables in SPSS give you all the information you need to compute proportion of variance.
The decision for a one-sample t-test is: Reject the null
hypothesis, since the p-value is less than the 0.05 alpha
level.
d = absolute value of Mean difference/sample standard deviation =
1.39/1.29 = 1.0776. This indicates that the effect size is large.
The scores have shifted in the population by 1.0776 standard
deviations.
r2 = d2/(d2 + 4) = 0.2250. This
indicates that the effect size is small. This means that 22.5% of
the proportion of variance in the dependent variable can be
explained by the factor.
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