Question

A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n independent trials of the experiment.

nequals=4040​,

pequals=0.980.98​,

xequals=3838

Upper P left parenthesis 38 right parenthesisP(38)equals=nothing

​(Do not round until the final answer. Then round to four decimal places as​ needed.)

A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n independent trials of the experiment.

n equals 9n=9​,

p equals 0.7p=0.7​,

x less than or equals 3x≤3

The probability of

x less than or equals 3x≤3

successes is

nothing.

​(Round to four decimal places as​ needed.)

Answer 1

Answer)

Answer)

Answer)

Here we need to use the binomial formula

P(r) = ncr*(p^r)*(1-p)^n-r

Ncr = n!/(r!*(n-r)!)

N! = N*n-1*n-2*n-3*n-4*n-5........till 1

For example 5! = 5*4*3*2*1

Special case is 0! = 1

P = probability of single trial = 0.98

N = number of trials = 40

R = desired success = 38

P(38) = 40c38*(0.98^38)*(1-p)^40-38

P(38) = 0.14479230116= 0.1448

Second)

P=0.7

N = 9

X = <=3

Required probability is

P(0)+p(1)+p(2)+p(3)

Afted substitution

P(x<=3) = 0.025294842 = 0.0253