Steel rods are manufactured with a mean length of 23 centimeter (cm). Because of variability in the manufacturing process, the lengths of the rods are approximately normally distributed with a standard deviation of 0.07 cm.
(a) What proportion of rods has a length less than 22.9 cm?
(b) Any rods that are shorter than22.83 cm or longer than 23.17 cm are discarded. What proportion of rods will be discarded?
(c) Using the results of part (b), if 5000 rods are manufactured in a day, how many should the plant manager expect to discard? Use the answer from part b to find this answer. Round to the nearest integer as needed.)
(d) If an order comes in for 10,000 steel rods, how many rods should the plant manager expect to manufacture if the order states that all rods must be between 22.9 cm and 23.1 cm? (Round up to the nearest integer.)
Hello Sir/ Mam
Given that:
Mean = | 23.00 |
Standard Deviation = | 0.07 |
(a)
(b)
Hence,
1.52% of the rods will be discarderd.
(c)
No. of rods to be discarded = 5000*1.52% = 75.79 approximately equal to 76 rods.
(d)
Hence,
No. of rods to be manufactured = 10000/84.69% = 11808 rods
I hope this solves your doubt.
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